2. I have a table with Username and SummedHourCount columns. My goal is to select the username where (SummedHourCount / SUM(SummedHourCount)) > 3/4. SUM(SummedHourCount) meaning all of the hours present in the column. For example, if I have the following data: Username. SummedHourCount. randy.jackson. 13.
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Having clause is used to filter the result set of the aggregate functions like (COUNT,min,max etc) they eliminate rows based from groups based on some criteria like this :- SELECT dept_no, MIN(salary), MAX(salary), AVG(salary) FROM employee WHERE dept_no IN (100,300,500,600) GROUP BY dept_no HAVING AVG(salary) > 37000; The QUALIFY clause eliminates rows based on the function value, returning a ...
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I think I've got this one (but perhaps there is a simpler method). I'm using: SELECT Type, Color, Count(Location) FROM. (SELECT DISTINCT Type, Color, Location FROM MyTable) GROUP BY Type, Color HAVING Count(Location)>1; How can I create another query that lists the Type, Color, and Location for each distinct Type,Color when the count of unique ...
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WHERE s.SalesOrderID = s2.SalesOrderID. GROUP BY SalesOrderID. HAVING COUNT(*) > 1. AND COUNT(CASE WHEN OrderQty > 1 AND ProductID = 777 THEN 1 END) >= 1. ); What I don't understand is this: The sub-query returns a single-columned table filled with the value 1 on each row. So the way I understand it, the WHERE in the outer query has no real ...
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11. There is no need to do two checks, why not just check for count = 3: GROUP BY meetingID. HAVING COUNT(caseID) = 3. If you want to use the multiple checks, then you can use: GROUP BY meetingID. HAVING COUNT(caseID) > 2. AND COUNT(caseID) < 4.
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1. We can use aggregate function with HAVING clause not by WHERE clause e.g. min,max,avg. 2. WHERE clause eliminates the record tuple by tuple HAVING clause eliminates entire group from the collection of group. Mostly HAVING is used when you have groups of data and WHERE is used when you have data in rows.
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FROM Employees; SQLFIDDLE. However, if there are multiple people with the same minimum salary then this will only get the one with the name which is first alphabetically. You can get all the names, but it does require multiple SELECT statements: SELECT first_name, salary. FROM Employees. WHERE salary = ( SELECT MIN(salary) FROM Employees ); But ...
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HAVING: is used to check conditions after the aggregation takes place. WHERE: is used to check conditions before the aggregation takes place. This code: select City, CNT=Count(1) From Address. Where State = 'MA'. Group By City. Gives you a table of all cities in MA and the number of addresses in each city. This code:
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You can use TOP and ORDER BY for this: SELECT TOP 1. d.ID AS dep_id, sum(u.Salary) AS Sum_Salary. from dbo.users u. INNER JOIN Departments d ON u.DepartmentID=d.id. GROUP BY d.ID. order by Sum_Salary desc; It'll return the top 1 row with maximum Sum_salary.
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58. Not really. The having clause implies an aggregation, which means you don't have the original rows any more. I think you want the following: DELETE from UserPredictions. where UserId in (select UserId from UserPredictions group by UserId having count(*) < 500) answered Jul 29, 2012 at 1:52. Gordon Linoff.
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